What is the equation of the line that passes through the point (6,3) and has a slope
of -1/3?

Answer:
y = - [tex]\frac{1}{3}[/tex] x + 5
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Here m = - [tex]\frac{1}{3}[/tex] , then
y = - [tex]\frac{1}{3}[/tex] x + c ← is the partial equation
To find c substitute (6, 3 ) into the partial equation
3 = - 2 + c ⇒ c = 3 + 2 = 5
y = - [tex]\frac{1}{3}[/tex] x + 5 ← equation of line