Triangle ABC is a right triangle. What is the length of AC?

Answer:
AC = [tex]\sqrt{58}[/tex]
Step-by-step explanation:
Calculate AC using the distance formula
d = [tex]\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }[/tex]
with (x₁, y₁ ) = A (0, - 2) and (x₂, y₂ ) = C (3, 5 )
AC = [tex]\sqrt{(3-0)^2+(5-(-2)})^2[/tex]
= [tex]\sqrt{3^2+(5+2)^2}[/tex]
= [tex]\sqrt{9+7^2}[/tex]
= [tex]\sqrt{9+49}[/tex]
= [tex]\sqrt{58}[/tex]