We have that since [tex]F_1[/tex] is moving to the right and its greater
The direction of Net force is 50m/s to the Right
Option A is correct
From the Question we are told that
Force 1 [tex]F_1=100[/tex]
Force 2 [tex]F_2=50[/tex]
Generally the Net force of two forces opposing each other is the difference between them
Therefore
The Net force between Force 1 and 2 is
[tex]F_t=F_1-F_2[/tex]
[tex]F_t=100-50[/tex]
[tex]F_t=50/s[/tex]
In conclusion
Since [tex]F_1[/tex] is moving to the right and its greater
The direction of Net force is 50m/s to the Right
Option A is correct
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