Using proportional relations, it is found that:
- The equation for the relationship is [tex]\frac{x}{60}[/tex].
- [tex]\frac{5}{12}[/tex] cups is recommended for a 25- pound adult dog.
-------------------------------
The amount of cups of food y is proportional to the weight of a dog, which is of x pounds, and thus, the following equation models the situation:
[tex]y = cx[/tex]
In which c is the constant of proportionality.
-------------------------------
- [tex]\frac{1}{6}[/tex] of a cup is needed to feed a dog of 10 lbs.
- This means that when [tex]x = 10, y = \frac{1}{6}[/tex]
- This is used to find c.
[tex]y = cx[/tex]
[tex]\frac{1}{6} = 10c[/tex]
[tex]60c = 1[/tex]
[tex]c = \frac{1}{60}[/tex]
Thus, the equation for the relationship is:
[tex]y = \frac{x}{60}[/tex]
-------------------------------
The amount of cups needed for a 25-pound dog is y when x = 25, thus:
[tex]y = \frac{25}{60} = \frac{5}{12}[/tex]
[tex]\frac{5}{12}[/tex] cups is recommended for a 25- pound adult dog.
A similar problem is given at https://brainly.com/question/22846068