Using a linear equation, it is found that:
The linear function is: [tex]C(n) = 50 + 15n[/tex]
The domain of the function is: [tex]D_C = [0,\infty)[/tex]
The range of the function is: [tex]R_C = [50,\infty)[/tex]
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The linear equation for her monthly bill, considering she goes to n classes, has the following format:
[tex]C(n) = C_f + an[/tex]
In which
- [tex]C_f[/tex] is the fixed cost.
- a is the cost per class.
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- Monthly bill of $50 plus $15 per class means that: [tex]C_f = 50, a = 15[/tex].
Thus, the linear function is:
[tex]C(n) = 50 + 15n[/tex]
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- The domain is the input, that is, n, the number of classes she can go. It is of 0 or greater, thus: [tex]D_C = [0,\infty)[/tex].
- The range is the output, that is, C, the possible costs, which ranges from 50(0 classes), to infinity, and thus: [tex]R_C = [50,\infty)[/tex].
A similar problem is given at https://brainly.com/question/10891721