6. Teri estimates that it will cost $200,000 to send his daughter to a private college in 16
years. He currently has $125,000 to deposit in an account. What simple interest rate
would
he need so that $125,000 grows info $200,000 in 16 years? Round to the nearest
percent.


How do I solve this?

Respuesta :

The simple interest rate need by Teri will be 4%.

Step-by-step explanation:

Given:

Teri has $125,000 to deposit in his accounts so that he gets $200,000 in 16 years along with the simple interest.

To find:

The simple interest rate needed to grow $125,000 into $200,000 in 16 years.

Solution:

The principle amount Teri has = P = $125,000

The total amount Teri wants to have in 16 years = A = $200,000

The simple interest that will Teri earn = S.I

[tex]S.I= A - P =\$200,000-$125,000=\$ 75,000[/tex]

The rate of interest per year = R

The time for which money is deposited = T = 16 years

The simple interest is calculated by the formula:

[tex]S.I=\frac{P\times R\times T}{100}\\\$75,000=\frac{\$125,000\times R\times 16}{100}\\R=\frac{$75,000\times 100}{$125,000\times 16}=3.75\% \approx 4\%[/tex]

The simple interest rate need by Teri will be 4%.

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Simple interest rate (R) is 3.75%

Given:

Amount deposit as saving (P) = $125,000

Number of year (n) = 16 year

Amount needed (A) = $200,000

Find:

Simple interest rate (R)

Computation:

Amount of interest (I) = A - P

Amount of interest (I) = 200,000 - 125,000

Amount of interest (I) = 75,000

So,

I = (P)(R)(T)

75,000 = (125,000)(R)(16)

75,000 = 2,000,000(R)

R = 75,000 / 2,000,000

R = 0.0375

Simple interest rate (R) = 3.75%

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