Answer:
Step-by-step explanation:
J (-1,4) ⇒ x₁ = -1 & y₁ = 4
K(5,-3) ⇒ x₂ = 5 ; y₂ = -3
m : n = 1/3 : 2/3 = 1 :2
[tex]X \left(\dfrac{mx_{2}+nx_{1}}{m+n},\dfrac{my_{2}+ny_{1}}{m+n} \right)\\\\\\X \left(\dfrac{1*5+2*(-1)}{1+2},\dfrac{1*(-3)+2*4}{1+2} \right) \\\\\\X \left(\dfrac{5-2}{3},\dfrac{-3+8}{3} \right)\\\\\\X \left(\dfrac{3}{3},\dfrac{5}{3} \right)\\\\\\X \left( 1 , \dfrac{5}{3} \right)[/tex]
