plz help me with this question dueto 12:15 plz

[tex]fog(x) = f(g(x)) \\ 6x - 2 = 3(g(x)) - 2 \\ \\ 3g(x) = 6x - 2 + 2 \\ 3g(x) = 6x \\ \\ g(x) = \frac{6x}{3} \\ g(x) = 2x[/tex]
[tex]gof)^{ - 1} (x) = \frac{1}{g(f(x))} \\ \\ 8 = \frac{1}{2(3x - 2) } \\ \\ 8 = \frac{1}{6x - 4} \\ \\ 8(6x - 4) = 1 \\ \\ 48x - 32 = 1 \\ \\ 48x = 1 + 32 \\ 48x = 33 \\ \\ x = \frac{33}{48} \\ \\ x= 0.6875[/tex]
I hope I helped you^_^