Carlos can put the blocks in this three ways:
(i) 32 large blocks and 4 small blocks.
(ii) 22 large blocks and 5 small blocks.
(iii) 12 large blocks and 6 small blocks.
The total quantity of blocks equals the number of blocks stored in the sets of blocks. Based on the information given, we derive the following algebraic expression:
[tex]10\cdot m + 100\cdot n = 720[/tex], [tex]\forall\,m,n\in \mathbb{N_{O}}[/tex] (1)
Where:
Now we can clear [tex]n[/tex] in terms of [tex]m[/tex]:
[tex]100\cdot n = 720 -10\cdot m[/tex]
[tex]n = 7.2-0.1\cdot m[/tex] (2)
From (2) we get the following combination of sets:
1) [tex]m = 12, n= 6[/tex]
2) [tex]m = 22, n = 5[/tex]
3) [tex]m = 32, n = 4[/tex]
Carlos can put the blocks in this three ways:
(i) 32 large blocks and 4 small blocks.
(ii) 22 large blocks and 5 small blocks.
(iii) 12 large blocks and 6 small blocks.
We kindly invite to see this question on linear functions: https://brainly.com/question/3400735
