The sum of three even consecutive integers if the first integer is y will be 3y + 6.
First integer = y
Second integer = y + 2
Third integer = y + 4
Therefore, based on the expressions given above, the sum of the three integers will be:
= y + y +2 + y + 4
= 3y + 6
Therefore, the sum will be 3y + 6.
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