Answer:
x < - [tex]\frac{1}{3}[/tex] or x > [tex]\frac{13}{9}[/tex]
Step-by-step explanation:
Inequalities of the type | x | > a have solutions of the form
x < - a OR x > a
Then
| - 9x + 5 | > 8 has solutions
- 9x + 5 < - 8 ( subtract 5 from both sides )
- 9x < - 13
Divide both sides by - 9, reversing the symbol as a result of dividing by a negative quantity.
x > [tex]\frac{13}{9}[/tex]
OR
- 9x + 5 > 8 ( subtract 5 from both sides )
- 9x > 3
Divide both sides by - 9, reversing the symbol as a result of dividing by a negative quantity.
x < [tex]\frac{3}{-9}[/tex]
x < - [tex]\frac{1}{3}[/tex]
Solution is x < - [tex]\frac{1}{3}[/tex] or x > [tex]\frac{13}{9}[/tex]
