Answer:
[tex] 1 \frac{9}{80} [/tex]
Step-by-step explanation:
To solve this you have to use BODMAS theorem
BODMAS means,
B = brackets
O = of
D = division
M = multiplication
A = addition
S = subtraction
In this sum first you have to do division and then you can do addition
Let's Solve now,
[tex]m + n \div m - n \\ \frac{4}{5} + \frac{5}{4} \div \frac{4}{5} - \frac{5 }{4} \\ \frac{4}{5} + \frac{5}{4} \times \frac{5}{4} - \frac{5}{4} \\ \frac{4}{5} + \frac{25}{16} - \frac{5}{4} \\ \frac{4 \times 16 + 25 \times 5}{5 \times 16} - \frac{5}{4} \\ \frac{64 + 125}{80} - \frac{5}{4} \\ \frac{189}{80} - \frac{5}{4} \\ \frac{189}{80} - \frac{5 \times 20}{4 \times 20} \\ \frac{189 - 100}{80} \\ \frac{89}{80} \\ = 1 \frac{9}{80} [/tex]
hope this helps you
let me know if you have another questions :-)
