- It is important to note that:
A nickel = $0.05
A dime = $0.10
We would be representing,
The number of nickels = n
The number of dimes = d
- Kendra has $3.15 in dimes and nickels. Writing this statement as an algebraic expression:
0.05n + 0.10d = 3.15...............Equation 1
- She has 4 times as many dimes as nickels. The algebraic expression for this statement :
4n = d ........................................ Equation 2
We would substitute 4n for d in Equation 1
0.05n + 0.10 x 4n = 3.15...............Equation 3
0.05n + 0.4n = 3.15
0.45n = 3.15
Divide both sides by 0.45
0.45n/0.45 = 3.15/0.45
n = 7
The number of nickels is 7
We solve for d, the number of dimes
4n = d
n = 7
4 x 7 = d
28 = d
The number of dimes is 28
Therefore, Kendra has 7 nickels and 28 dimes
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