An 11.5 mg sample of blood containing 11.1 micrograms of Fe in hemoglobin, with a 3.83% by mass of heme, has a mass percent of hemoglobin of 27.9%.
The molar mass of heme (C₃₄H₃₂FeN₄O₄) is 616.49 g/mol. Since each mole of heme contains 1 mole of Fe (55.85 g/mol), there are 55.85 g of Fe per 616.49 g of heme. The mass of heme that contains 11.1 μg (11.1 × 10⁻⁶ g) of Fe is:
[tex]11.1 \times 10^{-6} g Fe \times \frac{616.49g Heme}{55.85gFe} = 1.23 \times 10^{-4} g Heme[/tex]
Hemoglobin contains 3.83% by mass of heme. The mass of hemoglobin that contains 1.23 × 10⁻⁴ g of Heme is:
[tex]1.23 \times 10^{-4} g Heme \times \frac{100gHemoglobin}{3.83gHeme} = 3.21 \times 10^{-3} g[/tex]
3.21 × 10⁻³ g of Hemoglobin are in 11.5 mg (11.5 × 10⁻³ g) of blood. The mass percent of hemoglobin in the blood sample is:
[tex]\% Hemoglobin = \frac{mass\ Hemoglobin}{mass\ blood} \times 100 \% = \frac{3.21 \times 10^{-3}g }{11.5 \times 10^{-3}g} \times 100 \% = 27.9 \%[/tex]
An 11.5 mg sample of blood containing 11.1 micrograms of Fe in hemoglobin, with a 3.83% by mass of heme, has a mass percent of hemoglobin of 27.9%.
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