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4. The Crazy Candy Company ships out chocolates in boxes of 4 candies and boxes of 10
candies. Two orders are placed, one has only boxes of 4 candies and one only has boxes of 10
candies. The two orders contain the same number of chocolate candies.
(a) What is smallest number of candies each order could have contained? Explain.

Respuesta :

Using the least common multiple of 4 and 10, it is found that the smallest number of candies each order could have contained is 20 candies.

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  • There are boxes of 4 candies and of 10 candies.
  • Thus, the smallest possible number of equal candies on two orders in the least common multiple of 4 and 10.
  • To find this multiple, we factor both numbers by their prime factors, thus:

4 - 10|2

2 - 5|2

1 - 5|5

1

Thus, lcm(4,10) = 2*2*5 = 20.

  • The smallest possible number is 20 candies, one order with 20/4 = 5 boxes of 4 candies, and the other with 20/10 = 2 boxes of 10 candies.

A similar problem is given at https://brainly.com/question/24540608

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