If you can answer both, please do. But if you can't, just answer one.

1. What average net force is required to stop a 7 kg shopping cart in 2 s if it’s initially traveling at 3.5 m/s?

2. What average net force is required to stop an 8500 kg truck in 10 s if it’s initially traveling at 20 m/s?

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pixleshooterisback pixleshooterisback · Answer 1 · 2021-09-22T00:11:37+02:00

Answer:

1.The force required to stop the shopping cart is, F = 12.25 N

Explanation:

Given data,

The mass of the shopping cart, m = 7 kg

The initial velocity of the shopping cart, u = 3.5 m/s

The final velocity of the shopping cart, v = 0 m/s

The time period of acceleration, t = 2 s

The change in momentum of the cart,

p = m(u - v)

= 7 (3.5 - 0)

= 24.5 kg m/s

The force is defined as the rate of change of momentum. To stop the shopping cart, the force required is given by the formula

F = p / t

= 24.5 / 2

= 12.25 N

Hence, the force required to stop the shopping cart is, F = 12.25 N

2.

We have: F = m × v/t

Here, m = 8500 Kg

v = 20 m/s

t = 10 s

Substitute their values into the expression,

F = 8500 × 20/10

F = 8500 × 2

F = 17000 N

In short, final answer would be 17000 N

Hope this helps!!