During glycolysis, PEP goes through a reaction involving a loss of phosphate group to ADP, with pyruvate and ATP resulting. Thus, the correct option would be B.
The process of PEP going through a loss of phosphate group to become pyruvate represents one of the key steps in glycolysis.
Glycolysis is a metabolic process whereby glucose molecules are broken down into pyruvate or lactate in the presence or absence of oxygen respectively.
The steps involved in glycolysis can be summarized as follows:
- An enzyme catalyzes the conversion of glucose to glucose-6-phosphate (G6P).
- Another enzyme, phosphoglucomutase, converts G6P to its isomer - fructose-6-phosphate (F6P)
- F6P further gets another phosphate, resulting in fructose-1,6-biphosphate.
- fructose-1,6-biphosphate is split into dihydroxyacetone phosphate and glyceraldehyde 3-phosphate.
- the dihydroxyacetone phosphate is converted to glyceraldehyde 3-phosphate. Thus, 2 molecules of glyceraldehyde 3-phosphate now result.
- the 2 molecules of glyceraldehyde 3-phosphate each undergo dehydrogenation and phosphorylation to become 1,3-biphosphoglycerates
- Each 1,3-biphosphoglycerate loses a phosphate group to ADP, resulting in the formation of 2 molecules of ATP and 3-phosphoglycerate respectively.
- the phosphate group in 3-phosphoglycerate is relocated to become 2-phosphoglycerate
- each 2-phosphoglycerate molecule undergo a dehydration reaction, resulting in the formation of phosphoenolpyruvate (PEP)
- the phosphate group in PEP is transferred to ADP resulting in the formation of ATP and pyruvate respectively.
More on glycolysis can be found here: https://brainly.com/question/10886602
