we know the complex number has standard form a+ib
Inorder to find our answer ib^2 should.be 1
Ex:-
2-i
2:-
[tex]\\ \sf\longmapsto 2+2i^2[/tex]
2 + i^2 = 1. also i^4 = 1
3 + i^2 = 2 also 2i^4 = 2
4 + i^2 = 3 also 3i^4 = 3
the complex series has a form Z = a + ib, where a is the real number and ib is the imaginary part.
we know i = √-1 so i^2 = -1 and (i^2)^2 = (-1)^2 = 1. or i^4 = 1.
also,
2 + i^2 = 1. since i^2 = -1, 2 + -1 = 2-1 = 1.
if we want to find 2,
3 + i^2 = 2. since we know i^2 will be -1, set the a value to be 1 more the value you need. for example if you want 3, set a to be 4.
for 3.
first make a to be 1 more than 3 which is 4.
3 = 4 + i^2.
