Respuesta :
Speed or Velocity is the distance at which a person or object is moving per time.
The car with the highest average velocity is Car B
It would take Car A 7.33 hours to travel the same distance as Car B
We would solve the question in two parts.
Part A
The formula used to calculate the average velocity is :
Distance (km) / Time (hr)
- Step 1: We solve for the average velocity for Car A. Car A traveled 1200 km in 8 h.
Average velocity for Car A = 1200 km/8 hr
= 150 km/hr
- Step 2: We solve for the average velocity for Car B. Â Car B traveled 1100 km in 6.5 h.
Average velocity for Car B = 1100 km/ 6.5 hr
= 169.23 km/hr
- Step 2: We solve for the average velocity for Car C. Â Car C traveled 1300 km in 8.3h.
Average velocity for Car C Â = 1300 km/ 8.3 hr
= 156.63 km/hr.
Therefore, the car with the highest average velocity is Car B
Part B
How long would it have taken the slowest car to travel the same distance as the fastest car?
The slowest car is Car A with an average velocity of 150 km/hr
The time it would take for Car A to drive the same distance as Car B is calculated using the formula
Time = Distance of Car B/ Average velocity of Car A
Distance of Car B = 1100 km
Average velocity of Car A = 150 km/ hr
Time = 1100km / 150 km/hr
= 7.33 hours
Therefore, it would take Car A 7.33 hours to travel the same distance as Car B
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https://brainly.com/question/14691588
