Using proportions, it is found that:
- The length of her actual office is of 10 ft.
- The width of her actual office is of 5 ft.
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- Scale problems are solved using proportions, by a rule of three.
- The scale is of 6 cm to 15 ft, which means that each 6 cm in the drawing represents 15 ft of real dimensions.
In the drawing, the length is of 4 cm, thus:
4 cm - x ft
6 cm - 15 ft
Applying cross multiplication:
[tex]6x = 60[/tex]
[tex]x = \frac{60}{6}[/tex]
[tex]x = 10[/tex]
The length of her actual office is of 10 ft.
The width is of 2 cm, thus:
2 cm - x ft
6 cm - 15 ft
Applying cross multiplication:
[tex]6x = 30[/tex]
[tex]x = \frac{30}{6}[/tex]
[tex]x = 5[/tex]
The width of her actual office is of 5 ft.
A similar problem is given at https://brainly.com/question/24105256
