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A car is traveling at a velocity of 22 m/s when the driver puts on the brakes
to decelerate it at 1.4 m/s2
over a distance of 110 m. What is the car’s velocity at the end of this distance?

Respuesta :

Lanuel

The car’s velocity at the end of this distance is 18.17 m/s.

Given the following data:

  • Initial velocity, U = 22 m/s
  • Deceleration, d = 1.4 [tex]m/s^2[/tex]
  • Distance, S = 110 meters

To find the car’s velocity at the end of this distance, we would use the third equation of motion;

Mathematically, the third equation of motion is calculated by using the formula;

[tex]V^2 = U^2 + 2dS[/tex]

Substituting the values into the formula, we have;

[tex]V^2 = 22 + 2(1.4)(110)\\\\V^2 = 22 + 308\\\\V^2 = 330\\\\V^2 = \sqrt{330}[/tex]

Final velocity, V = 18.17 m/s

Therefore, the car’s velocity at the end of this distance is 18.17 m/s.

Read more: https://brainly.com/question/8898885

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