An object in free fall motion is under the influence of gravitational force only
The height and time are;
(a) The height of the cliff, h ≈ 8.00 meters
(b) The time it takes the rock to rich the ground with the same speed going downward is approximately 0.67 seconds
The reason the above values are correct are as follows:
The given parameters are;
The time it takes for the rock to hit the ground when thrown straight up from the cliff, t = 2.45 s
The initial velocity with which the rock is thrown, u = 8.75 m/s
(a) To find the height of the cliff
Solution
The kinematic equation of motion is s = y₀ + u·t + (1/2)·g·t²
The time it takes to maximum height, [tex]t_{max}[/tex] = 8.75/9.81
The time it takes to get back to the cliff edge when thrown = 2 × 8.75/9.81
The time taken to fall at the velocity of u downwards from the cliff edge, [tex]t_{cliff}[/tex], is given as follows;
[tex]t_{cliff}[/tex] = 2.45 - 2 × 8.75/9.81 ≈ 0.666
Height of cliff, h = 8.75×(2.45 - 2 × 8.75/9.81) + (1/2) × 9.81 × (2.45 - 2 × 8.75/9.81)² ≈ 8
The height of the cliff, h ≈ 8.00 meters
(b) The time it takes the rock to rich the ground when thrown straight down art the same speed, (calculates above) = [tex]t_{cliff}[/tex] ≈ 0.67 seconds
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