The acceleration of the box that has a mass of 4 kg and a coefficient of kinetic friction of 0.2, when moved by an exerted force of 58 N, is 10.06 m/s².  Â
The acceleration of the box can be calculated with the sum of the forces acting on the x-direction:
[tex] \Sigma F_{x} = ma [/tex]
We will not take into account the forces acting on the y-direction since we need to find the acceleration of the box when it is moving (x-direction).
[tex] T_{x} - F_{\mu} = ma [/tex] Â Â (1)
Where:
- [tex]T_{x}[/tex]: is the horizontal component of the tension force (T) exerted by the string on the box = T*cos(θ)Â
- θ: is the angle (from the horizontal) = 34°
- [tex]F_{\mu}[/tex]: is the force due to the kinetic friction = -μN (the minus sign is because it is in the opposite direction of motion) Â
- m: is the mass of the box = 4 kg
- a: is the acceleration =?
- μ: is the coefficient of kinetic friction = 0.2
- N: is the normal force = mg
- g: is the acceleation due to gravity = 9.81 m/s²
From equation (1) we have:
[tex] Tcos(34) - \mu N = ma [/tex] Â
[tex] Tcos(34) - \mu mg = ma [/tex] Â
Hence, the acceleration is:
[tex] 58N*cos(34) - 0.2*4 kg*9.81 m/s^{2} = 4 kg*a [/tex] Â
[tex] a = \frac{58N*cos(34) - 0.2*4 kg*9.81 m/s^{2}}{4 kg} = 10.06 m/s^{2} [/tex]
Therefore, the acceleration of the box when the box is moving is 10.06 m/s².
You can learn more about forces here:
- https://brainly.com/question/2008782?referrer=searchResults
- https://brainly.com/question/24611730?referrer=searchResults
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I hope it helps you!
