One star (star A) has a parallax of 3.4 arc seconds, while a second star (star B) has a parallax of 1.70 arc seconds. What can you correctly conclude?

Choose:
a) Star B must have a larger proper motion than Star A

b) Star A must have a larger proper motion than Star B

c) Star A is closer to Earth than Star B

d) Star B is closer to Earth than Star A

e) Both stars are outside the Milky Way galaxy.

Respuesta :

Based of the distance of each star, we can conclude that Star A must have a larger proper motion than Star B.

The given parameters;

  • parallax of star A = 3.4 arc seconds
  • parallax of star B = 1.7 arc seconds

The distance of each star form a Parallax is calculated as

[tex]d = \frac{1}{p}[/tex]

Where;

d is the distance to star, [parsecs]

p is parallax, [arc seconds]

The distance of star A;

[tex]d = \frac{1}{3.4} = 0.3 \ parsecs[/tex]

The distance of start B;

[tex]d = \frac{1}{1.7} = 0.6 \ parsecs[/tex]

On average, it is known that a nearby star will have a large proper motion.

Based on the distance of each star calculated above, star A is nearer and it will have a larger proper motion that star B.

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