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Using Kepler’s Law:
The mean distance between the earth and the sun is 1.5 x 10^11 m, the mean
distance between the sun and Mars is 2.287 x 10^11 m
What is the period of Mars around the Sun in Earth-days?


WILL GIVE BRAINLIEST !!

Respuesta :

Answer:

T^2 / D^3 = C     Square of period proportional to cube of mean distance

(365 da)^2 / (1.5E11 m)^3 = Tm^2 / (2.287 m)^3

Tm^2 = 365^2 * (2.287 / 1.5)^3 = 365^2 * 3.544

Tm = 365 * 1.883 = 687 da

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