When the fraction below is written as a decimal, how many digits are in the smallest sequence of repeating digits? 41/333 the answer choices are (1),(2),(3), or (4)

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The number of digits in the value of the decimal which are present in the smallest sequence of repeating digits are 3 which are 1, 2 and 3

When the expression 41/133 is expressed as a decimal, the decimal value obtained is ;

41/133 = 0.123123123...

The repeating digits in the decimal are the values 1, 2 and 3 and they are repeated in the sequence 123

Therefore, the Number of digits in the smallest sequence of the repeating digits is 3

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Answer:

C: 3

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