Answer:
#3: The equation needs to be in slope intercept form: y = mx + b
We can see that b (the y-intercept) is 13, because when x = 0 then y = 13
So we have y = mx + 13
Now substitute some other coordinates in this equatioin to find the slope
12.2 = m(4) + 13
-13 -13
-0.8 = m(4)
to make this easier turn the decimal into a fraction -0.8 = -8/10 = -4/5
-4/5 = m(4)
/4 /4
-1/5 = m
So the slope is -1/5 and the equation is y = -(1/5)x + 13
#4: Find the slope with this formula
[tex]\frac{y_{2}-y_{1}}{x_{2}-x_{1}} = \frac{-10 -(-4)}{8 - 4} = \frac{-6}{4} = \frac{-3}{2}[/tex]
Find the y-intercept
[tex]y = \frac{-3}{2}x + b[/tex]
Substitute a point, such as (4, -4)
[tex]-4 = \frac{-3}{2}(4) + b[/tex]
[tex]-4 = \frac{-12}{2} + b[/tex]
[tex]-4 = -6 + b[/tex]
[tex]-4 + 6 = -6 + 6 + b[/tex]
[tex]b = 2[/tex]
So the equation is [tex]y = \frac{-3}{2}x + 2[/tex]
#5: The slope is given. So the equation is [tex]y = 2x + b[/tex]
Substitute the (x, y) values given: (1, 9)
[tex]9 = 2(1) + b[/tex]
[tex]\frac{9}{2} = b[/tex]
So the equation is [tex]y = 2x + \frac{9}{2}[/tex]
Step-by-step explanation:
