I'm almost confident that I did this wrong, but i tried...
Answer:
4a-9 ÷ -19
Step-by-step explanation:
(It was easier for me to put it in fractions)
[tex]\frac{2(a-3)}{(a-4)(a-5)}[/tex] + [tex]\frac{a-1}{(3-a)(a-4)}[/tex] + [tex]\frac{a-2}{(5-a)(a-3)}[/tex] (3-a) (a-4) + (5-a) (a-3)
[tex]\frac{2a-6}{(a-4)(a-5)}[/tex] + [tex]\frac{a-1}{(3-a)(a-4)}[/tex] + [tex]\frac{a-2}{(5-a)(a-3)}[/tex] 3 - a · a - 4 + 5 - a · a - 3
[tex]\frac{2a-6}{(2a-20)}[/tex] + [tex]\frac{a-1}{(3-a)(a-4)}[/tex] + [tex]\frac{a-2}{(5-a)(a-3)}[/tex] 3 - a + 1 - a - 3
[tex]\frac{2a-6+a-1+a-2}{(2a-20)+(3-a)(a-4)+(5-a)(a-3)}[/tex] 1 - a - a
[tex]\frac{4a-9}{2a-20+1-2a}[/tex] 1 - 2a
[tex]\frac{4a-9}{2a-19-2a}[/tex]
[tex]\frac{4a-9}{-19}[/tex]
