Thornbred
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A ball is thrown from a hot air balloon that is at rest 245 m above the ground. How long will it take for the ball to reach the ground? How fast will the ball be traveling when it reaches the ground?

Respuesta :

Space

Answer:

7.07 s

69.3 m/s

Explanation:

Taking the negative direction to be down and the positive direction to be up:

We have 3 variables in the y-direction and can solve for time.

  • v₀ = 0 m/s
  • a = -9/8 m/s²
  • Δy = -245 m
  • t = ?

Use this kinematics equation to solve for time.

  • Δx = v₀t + 1/2at²
  • -245 = 1/2(-9.8)t²
  • -245 = -4.9t²
  • t² = 50
  • t = 7.07106781187

It will take the ball 7.07 s to reach the ground.

We can solve for final velocity using the same variables in the y-direction:

  • v₀ = 0 m/s
  • a = -9/8 m/s²
  • Δy = -245 m  
  • v = ?

Use this kinematics equation to solve for final velocity.

  • v² = v₀² + 2aΔx
  • v² = 2(-9.8)(-245)
  • v² = 4802
  • v = 69.2964645563

The ball will be traveling at a speed of 69.3 m/s at the instant before it reaches the ground.