The actual density of iron is 7.874 g/mL. In a laboratory investigation, Jason finds the density of a piece of iron to be 7.921 g/mL.

What is the percent error that is associated with Jason’s measurement?

Respuesta :

The percent error associated with Jason’s measurement is 0.596%.

HOW TO CALCULATE PERCENTAGE ERROR:

  • The percentage error of a measurement can be calculated by following the following process:
  1. Find the difference between the true value and the measured value of a quantity.
  2. Then, divide by the true value and then multiplied by 100

  • The true value of the density of iron is 7.874 g/mL
  • Jason observed value is 7.921 g/mL

Difference = 7.921 g/mL - 7.874 g/mL

Difference = 0.047 g/mL

Percentage error = 0.047/7.874 × 100

Percentage error = 0.596%.

Therefore, the percent error associated with Jason’s measurement is 0.596%.

Learn more: https://brainly.com/question/18074661?referrer=searchResults