(1) The distance traveled by Thomas is 190 m
(2) The displacement of Thomas is 100 m forward
(3) The velocity of Thomas is 0.056 m/s
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(1) Distance is the sum of the total path covered.
first distance to cafe = 100 m
second distance to library = 45 m
third distance back to the cafe = 45 m
The total distance = 100 + 45 + 45 = 190 m
The distance traveled by Thomas is 190 m
(2) Displacement is the change in the position of an object;
Initial displacement forward = (100 + 45) m
Final displacement backward = 45 m
The total displacement = 145 m - 45 m = 100 m forward
The displacement of Thomas is 100 m forward
(3) The velocity of Thomas is calculated as the change in displacement per change in time.
the change in displacement = 100 m
the time of motion, t = 30 mins = 30 x 60 = 1800 s
[tex]v = \frac{\Delta x}{\Delta t} = \frac{100 \ m}{1800 \ s} = 0.056 \ m/s[/tex]
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