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Consider the reaction of cesium metal with gaseous fluorine to produce cesium fluoride. How many cesium ions are on the
reactant side of the equation?
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pstnonsonjoku

There is only one cesium ion on reactant (left hand side) of the reaction equation.

The formation of cesium fluoride involves the combination of cesium ion and fluoride ion. Cesium fluoride is an ionic compound since it is composed of ions.

The reaction between cesium ions and fluoride ions to form cesium fluoride occurs as follows;

Cs^+ + F^- ------> CsF

So, there is only one cesium ion on reactant (left hand side) of the reaction equation.

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