Answer:
[tex]f = \frac{2(3g-5)}{d}[/tex]
Step-by-step explanation:
Given the equation, [tex]\frac{df + 10}{6} = g[/tex], for f:
Multiply 6 on both sides of the equation to remove the denominator on the left-hand side:
[tex](\frac{6}{1})(\frac{df + 10}{6} ) = g(\frac{6}{1})[/tex]
df + 10 = 6g
Next, subtract 10 on both sides of the equation:
df + 10 - 10 = 6g - 10
df = 6g - 10
Factor 6g - 10:
df = 2(3g - 5)
Multiply both sides by (1/d) to isolate f:
[tex](\frac{1}{d}) df = 2(3g - 5)(\frac{1}{d})[/tex]
[tex]f = \frac{2(3g-5)}{d}[/tex]
