Respuesta :

We have that  

An equation of the tangent line to the curve y = x sqrt{x} that is parallel to the line  y = 6 + 6x. is

  • [tex]y=6\ x\ X-32[/tex]

From the question we are told

Find an equation of the tangent line to the curve y = x sqrt{x} that is parallel to the line y = 6 + 6x.

Generally the equation for the Tangent  is mathematically given as

[tex]y= 6* x + k[/tex]

Where

[tex]\frac{3}{2}*\sqrt{x}=6\\\\x=16[/tex]

Therefore

The Resultant value of  y

[tex]Y=64[/tex]

[tex]Hence\\\\64=96 + c\\\\c=-32[/tex]

Therefore

An equation of the tangent line to the curve y = x sqrt{x} that is parallel to the line  y = 6 + 6x. is

  • [tex]y=6\ x\ X-32[/tex]

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