a rectangular pool is 8 feet wide and 12 feet long. a walk of uniform width surrounds the pool. if the total area of the walk and the pool is 320 square feet, how wide is the walk?

Respuesta :

The walk is  4 feet  wide

The width of the rectangular pool = 8 feet

The length of the rectangular pool = 12 feet

Let the width of the walkway be w

The combined length of the pool and walkway = 12 + 2w

The combined width of the pool and walk way = 8 + 2w

The total area of the walk and the pool = 320 square feet

Area = Length  x  Width

320   =  (12 + 2w)  ( 8  +  2w)

320  =  96  +  24w  +  16w   + 4w²

4w²  +  40w + 96 - 320  =  0

4w²  +  40w  - 224  = 0

w²   +  10w  -  56  =  0

w²  -  4w  +  14w  -  56  =  0

w(w  -  4)  +  14(w   -  4)   =  0

(w  -  4)(w   +  14)   =  0

w   -  4  =  0

w   =  4

w  +  14   =  0

w   =  -14

The width of the walk =   4  feet

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