Answer:
y = [tex]\frac{A}{3(3+x)}[/tex]
Step-by-step explanation:
A = 9y + 3yx for y,
The first step is to factor out the terms on the right-hand side of the equation:
A = 3y(3 + x)
Next, divide both sides by 3(3 + x) to isolate y:
[tex]\frac{A}{3(3 + x)} = \frac{3y(3 + x)}{3(3 + x)}[/tex] or rewrite this as: [tex]\frac{A}{3(3 + x)} = \frac{y*3(3 + x)}{3(3 + x)}[/tex]
Since 3(3 + x) cancel out on the right-hand side of the equation, the only variable left will be the unknown, y.
Therefore, the final answer is:
[tex]\frac{A}{3(3 + x)} = y[/tex]
