Answer:
Answer: 2
SOLUTION:
The slope intercept form of the line is y=mx+c, where m is the slope of the line and c is the y-intercept.
Change the equation 4x−2y=−1 in slope intercept form:
4x−2y=−1
−2y=−4x−1
y=2x+
2
1
Therefore, the slope of the line 4x−2y=−1 is m=2.
Since the parallel lines have same slope.
Hence, the slope of the line parallel to the line 4x−2y=−1 is m=2.
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Answer:
slope = - 4
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y = [tex]\frac{1}{4}[/tex] x - 3 ← is in slope- intercept form
with slope m = [tex]\frac{1}{4}[/tex]
Given a line with slope m then the slope of a line perpendicular to it is
[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{1}{\frac{1}{4} }[/tex] = - 4
