Respuesta :
Answer:
[tex] 16 {x}^{0} + 2 {x}^{2} {y}^{ - 1} \\ = 16 + 2\frac{ {x}^{2} }{y} (anyting \: power \: 0 = 1 ) \\ thank \: you[/tex]
Answer:
[tex] 16 {x}^{0} + 2 {x}^{2} {y}^{ - 1} \\ = 16 + 2\frac{ {x}^{2} }{y} (anyting \: power \: 0 = 1 ) \\ thank \: you[/tex]