At equilibrium, the sum of clockwise and anticlockwise moments about a point is zero
The mass of that balances the system is [tex]\underline {316.\overline 6}[/tex] kg
The normal reaction force at the fulcrum is 5,804.25 N
Rason:
The mass of the stick = 150.0 g
Mass m₁ on the left = 50.0 g, location = 30 cm to the left of m₂
Mass m₂ on the left = 75.0 g, location = 40 cm to the left of the fulcrum
Mass m₃ on the right of the fulcrum. location = 30 cm to the right of the fulcrum
Required:
To find the mass of m₃
Solution:
Taking moment about the fulcrum, we have;
50 × (30 + 40) + 75 × (40) + 150 × 20 = m₃ × 30
9,500 = m₃×30
[tex]m_3 = \dfrac{9,500}{30} = 316. \overline 6[/tex]
The mass of that balances the system when it is attached at the right end of the stick, m₃ = [tex]316.\overline 6[/tex] kg
Normal reaction at the fulcrum = (50 + 75 + 150 + [tex]316.\overline 6[/tex]) × 9.81 = 5804.25
The normal reaction at the fulcrum is 5,804.25 N
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