The percentage error in the student's measurement would be 12.5%.
If the molecular mass of O2(g) is 32.0, it means that 1 mole of the gas weighs 32.0.
A student then measured the mass of 1 mole of O2(g) to be 28.0 (instead of 32). Thus, the student has made some errors in their measurement:
Absolute error = true value - measured value
= 32 - 28
= 4.0
Percentage error = error/true value x 100
= 4/32 x 100
= 12.5%
More on error calculation can be found here: https://brainly.com/question/17928273