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Suppose a 1.0-mL air bubble is trapped in the tip of your burst and you don't notice it before measuring out liquid smoke with the buret.burnt. What percentage error would be introduced in a 35.0 mL sample of liquid if the air bubble comes our of the tip of the burst while the liquid sample is being transferred?

Respuesta :

onyebuchinnaji

The percentage error introduced in the sample is 2.86%.

The given parameters;

error observed, = 1.0 mL

expected measurement = 35 mL

The error in this measurement will occur when the trapped air escapes.

  • This will reduce the value of the expected measurement.
  • This percentage error is the ratio of the error observed to the expected value.

The percentage error is calculated as follows;

[tex]\% \ Error = \frac{Error}{Expected \ measurement} \times 100\%\\\\\% \ Error = \frac{1}{35} \times 100\% \\\\\% \ Error = 2.86\%[/tex]

Thus, the percentage error introduced in the sample is 2.86%.

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