Respuesta :

S1NGH

Answer:

7² × a²b³

Step-by-step explanation:

→ Minus the powers of 7 from each other

[tex]\frac{7^{2}a^{10}b^{7} c^{12} }{a^{8}b^{4} c^{12} }[/tex]

→ Minus the a powers from each other

[tex]\frac{7^{2}a^{2}b^{7} c^{12} }{b^{4} c^{12} }[/tex]

→ Minus the b and c powers from each

[tex]{7^{2}a^{2}b^{3}[/tex]

Answer:

[tex] \frac{ {7}^{8} \times {a}^{10}b ^{7} {c}^{12}}{{7}^{6} \times {a}^{8}b ^{4} {c}^{12}} \\ = {7}^{8 - 6} a^{10 - 8} {b}^{7 - 4} c ^{12 - 12} \\ = {7}^{2} {a}^{2} {b}^{3} {c}^{0} \\ = 49 {a}^{2} {b}^{3} [/tex]

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