Respuesta :

jimmyzayn692

t1 = 8m+1, (first term)

t2 = 6m-2 (second term)

t3 = 3m-2 (Third term)

t2-t1= t3-t2

(6m-2)-(8m+1) = (3m-2)-(6m-2)

6m-2-8m+1 = 3m-2–6m-2

6m-8m-2+1 = 3m-6m-2-2

-2m-1 = -6m-4

-2m+6m= -4+1

4m=3

m= 3/4

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