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A student swings a container of water in a vertical circle of radius 1.0 m. Calculate the minimum speed of the container so that the water remains in the container at the top of the circle. ANS. 3.1 m/s E-4, P-12?​

Respuesta :

Answer:

Explanation:

The centripetal acceleration requirement must equal gravity at the top of the circle

mg = mv²/R

  v = √Rg

  v = √(1.0(9.8))

  v = 3.1304951...

  v = 3.1 m/s

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