A lighthouse, L, is 15 km due west of a port, P.
A ship, S, is 8 km due north of the lighthouse, L.
N
S
Not drawn
accurately
8 km
N
L
Р
15 km
The ship leaves its position at 12 noon.
It sails directly to the port at a speed of 8.5 km/h.
What time will it reach the port?

A lighthouse L is 15 km due west of a port P A ship S is 8 km due north of the lighthouse L N S Not drawn accurately 8 km N L Р 15 km The ship leaves its positi class=

Respuesta :

Here, we are required to determine what time the ship will reach the port.

The time taken by the ship to sail directly to the port is 2 hours

The point L is a right angle between the lines SL and LP.

The lines joining the position of the ship, S , the lighthouse, L and the port, P therefore forms a right-angle triangle.

Therefore, since Line SP is the hypothenuse obviously,

By Pythagoras theorem;

(SP)² = (LP)² + (SL)²

where, LP = 15km and SL = 8km

(SP)² = (15)² + (8)²

(SP)² = (15)² + (8)²(SP)² = 289

SP = √289 = 17km

Therefore, the distance sailed by the ship directly to the port is; 17km.

Therefore, if the speed of the ship is 8.5km/h.

Speed = Distance/Time.

By subject of formula change;

Time = Distance/Speed

Time = Distance/SpeedTime = 17/8.5

Time = 2 hours.

Ultimately, the time taken by the ship to sail directly to the port is 2 hours.

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