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The ages of three friends are consecutively one year apart. Together, their ages total 66 years. Which equation can be used to find the age of each friend (where represents the age of the youngest friend)?

x=____.

Respuesta :

SuhanaWagle

Answer:

First friend = 21 years

Second friend = 22 years

Third friend =23 years

Step-by-step explanation:

Age of first friend = x

Age of second friend = x+ 1

Age of third friend = x+ 2

Sum of ages = 66

(x) + (x+1) +(x + 2) = 66

3x + 3 = 66

3x = 66-3

3x = 63

x = [tex]\frac{63}{3}[/tex]

x= 21

First friend = x = 21 years

Second friend = x+1 = 21 +1 =22 years

Third friend = x+2 =21 +2 =23 years

Hope this helps.

Answer:

21, 22, and 23 years old.

Step-by-step explanation:

1) x

2) x+1

3) x+2

x + x +1 + x + 2 = 66

3x +3 = 66

3x = 66-3

x = 63/3

x = 21

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