Saniyah2005
contestada

In a friendly soccer game, you hit a ball with a speed of 13 m/s at an angle of 24 degrees above the
horizontal. (A) How long does it take for the ball to reach the goal if it is 4.2 meters away? (B) How high is the
ball when it reaches the goal?

Respuesta :

a) V= 13m/s at 24 degrees
X component of velocity Vx= V*cos24 =11.876 m/s
distance =4.2 meter
time =distance/speed =4.2/11.876 =0.3537 s
b) Vertical component of speed = Vy=vsin24=
5.29 m/s
s=ut+0.5at^2 =5.29880.3537-0.5*9.8*0.3537^2
=1.257 m above ground
pstnonsonjoku

The time of flight of the ball is 1.1 s and the maximum height attained is 1.42 m.

What is the time of flight?

The time of flight refers to the time that it takes for the ball to remain in air. The time of flight is given by;

T = 2usinθ/g

T = 2 * 13 m/s (sin24)/9.8 m/s^2

T = 1.1 s

The height that it reaches is obtained from;

H = v^2sin^2θ/2g

H = 27.96/19.6

H = 1.42 m

Learn more about projectile:https://brainly.com/question/11422992

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