We have that you can you prepare 450 ml of 1 X buffer A by adding 45ml of 10X buffer A with 405ml(450-45) of water
From the question we are told
If you have 100 ml of 10X Buffer A, how could you prepare 450 ml of 1 X buffer A
Generally the equation for the Concentration Volume relationship is mathematically given as
[tex]C1V1=C2V2\\\\Where\\\\C1=10X\\\\C2=1X buffer A\\\\V2=450ml \\\\Therefore\\\\V1=\frac{450*1}{10}\\\\V1=45ml[/tex]
Therefore
You can you prepare 450 ml of 1 X buffer A by adding 45ml of 10X buffer A with 405ml(450-45) of water
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