The value of x in CuSO4. xH2O is 5.
Given that;
Number of moles of anhydrous salt = Number of moles of hydrated salt
Number of moles of anhydrous salt = 319 × [tex]10^-3[/tex]
Mass of hydrated salt = 499 ×[tex]10^-3[/tex] g
Number of moles of anhydrous salt = 319 [tex]10^-3[/tex]g/160 g/mol = 0.00199 moles
Number of moles of hydrated salt = 499 × [tex]10^-3[/tex] g/ 160 + 18x
0.00199 = 499 × [tex]10^-3[/tex] g/ 160 + 18x
0.00199 (160 + 18x) = 499 ×[tex]10^-3[/tex]
0.318 + 0.036x = 0.499
0.036x = 0.499 - 0.318
0.036x = 0.181
x = 0.181/0.036
x = 5
Hence, x in CuSO4. xH2O is 5.
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