We have that the time is found by solving using the Newton's
as shown below
we have Time given as
t=2.78
From the question we are told
Generally the Newtons equation for the Distance is mathematically given as
[tex]S=Ut+0.5at^2\\\\Where\\\\U=Vsins\theta\\\\\ U=20sin20\\\\U=6.84[/tex]
Therefore
[tex]20=6.8t+0.5(9.8)t^2\\\\\t=\frac{8.84\pm\sqrt{-6.84^2-4(4.9(-20))}}{2*4.9}\\\\\t=\frac{8.84\pm 18.5799}{9.8}[/tex]
Therefore
[tex]t=\frac{8.84+18.5799}{9.8}\\\\t=2.79794898[/tex]
t=2.78
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